Finished and Deleted
I think this reads
x≥−1, Prove using induction that (1+x)n≥1+nx
P1=(1+x)1≥1+(1)xP1=(1+x)≥(1+x)=TRUE
Assume Pn is TRUE(1+x)n+1=(1+x)n(1+x)≥(1+nx)(1+x)=1+(n+1)x+nx2≥1+(n+1)xThus Pn⇒Pn+1△
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