The solutions of x(x-3)=1$ may be expressed in the form $\frac{a+\sqrt{b}}{c}$ and $\frac{a-\sqrt{b}}{c}$, where $a$, $b$, and $c$ are prime numbers. Find $abc$.
+23 ok ima try to help though im not hectiar. you dont have to listen, just im doing my best
The solutions of x(x-3)=1 may be expressed in the form \(\frac{a+\sqrt{b}}{c} \) and \(\frac{a-\sqrt{b}}{c}\), where a, b, and c are prime numbers. Find abc.
Ok. So if i understand, you can use the quadractic formula. distribute, and you get x^2-3x=1
simplify: x^2-3x-1=0
quadractic formulas it: you get a=3, b=13, c=2
i think....... multiply and you get 3*13*2
78? right? help me out people....
78
+23 im sorry. Im not hectair.......... 
