HELP PLZ!!!! DUE TODAY

Sorry, but the circle equation is not complete. It should be x^2 + y^2 = (missing part). What is that missing part?

I think https://www.khanacademy.org might help

I actually got the answer I just wanna double check. I have (3/5, -6/5)

First, you substitute y = (x - 3)/2 into x^2 + y^2 = 5.

You will get $x^2 + \left(\dfrac{x - 3}2\right)^2 = 5$

Now upon simplification, $5x^2 - 6x - 11 = 0$.

Notice that the solutions to this equation is the x-coordinates of A and x-coordinates of B respectively.

We conclude that the x-coordinate of the midpoint of AB is the sum of roots divided by 2, which is $\dfrac35$.

By a similar approach, you can find that the y-coordinate of the midpoint is $-\dfrac65$, which means your answer is correct.

Nvm I double checked and I got the correct one. Thank you

well we get slope 1/2 and we find points -1,2 and 2.2,0.4 to inersect w ethen use the pythangorean theorem to find the coorinates of midpoint AB is 3/5, -6/5