In triangle $ABC$, points $D$ and $F$ are on $\overline{AB},$ and $E$ is on $\overline{AC}$ such that $\overline{DE}\parallel \overline{BC}$ and $\overline{EF}\parallel \overline{CD}$. If $AF = 9$ and $DF = 3$, then what is $BD$?
Help pls
In triangle ABC, points D and F are on ¯AB, and E is on ¯AC such that ¯DE∥¯BC and ¯EF∥¯CD. If AF=9 and DF=3, then what is BD?
(1)¯AC¯AE=9+39(2)¯AC¯AE=9+3+BD9+3(1)=(2):¯AC¯AE=9+39=9+3+BD9+39+39=9+3+BD9+3129=12+BD1243=1+BD12BD12=43−1BD12=13BD=123BD=4