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How many three-digit multiples of 5 have three different digits?
How many three-digit multiples of 5 have three different digits and an odd tens digit?

 Jul 26, 2022
 #1
avatar+2666 
0

I'll do number 1, and let you solve for number 2...

 

For number 1, there are 2 choices for the units digit (0 or 5), 9 choices for the tens digit (anything but the units digit), and 8 choices for the hundreds digit (anything but the tens or unit digit).

 

This makes for \(2 \times 9 \times 8 = 144\)choices, but we aren't done yet...

 

Our answer includes numbers like \(085\), which isn't a 3-digit number. 

 

There is 1 choice for the hundreds digit, 8 choices for the tens digit, and 1 choice for the one's digit, which makes for \(1 \times 8 \times 1 = 8\) numbers. 

 

So, there are \(144 - 8 = \color{brown}\boxed{136}\) numbers that work

 Jul 26, 2022
 #2
avatar+275 
0

I got 72 for the second one but it is in correct
2*5*8 = 80
80-8
72

 Jul 26, 2022
 #3
avatar+2666 
0

There are 2 cases for number 2: the one digit is a 0, and the one's digit is a 5

 

For the former case: 1 choice for the one's digit, 5 choices for the 10s digit, and 8 choices for the hundreds digit, for \(8 \times 5 \times 1 = 40\)

 

For the latter case: 1 choice for the one's digit, 4 choices for the 10s digit (keep in mind we can't re-use 5), and 8 choices for the hundreds digit, for \(1 \times 4 \times 8 = 32\) numbers. 

 

But, we overcount for 015, 035, 075, and 095, making the total \(40 + 32 - 6 = \color{brown}\boxed{68}\)

 

Note that it is the same as the previous answer divided by 2. Can you figure out why?

BuilderBoi  Jul 26, 2022

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