What is the remainder when $2^{2005}$ is divided by 7?
$2^{2005}$ is divided by 7?
2^2005 mod 7 =2 Remainder.
22005(mod7)|26≡1(mod7)≡26⋅334+1(mod7)≡26⋅334⋅2(mod7)≡(26)334⋅2(mod7)|26≡1(mod7)≡(1)334⋅2(mod7)|(1)334=1≡1⋅2(mod7)≡2(mod7)