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There are three $20 bills, six $10 bills, seven $5 bills, and four$1 bills in your wallet. You select one bill at random. What is the expected value for this experiment? 

$ _______

 

 

You roll a pair of six-sided number cubes, numbered 1 through 6. What is the probability of rolling two odd numbers? (Enter your probability as a fraction.) 

=__________

 Nov 9, 2018
 #1
avatar+37170 
+1

Twenty bills

3/20 ($20)  + 6/20 (10) + 7/20(5) + 4/20(1) = 7.95 expected value

 Nov 9, 2018
 #2
avatar+6252 
+2

There are 20 total bills. Assume we choose any of them with equal probability.P[20]=320P[10]=620=310P[5]=720P[1]=420=15Let X be the value of the bill chosen.E[X]=20320+10310+5720+115E[X]=15920=$7.95

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 Nov 9, 2018
edited by Rom  Nov 9, 2018
 #3
avatar+37170 
0

3/6 are odd for each die

3/6 x 3/6 = 9/36 = 1/4 chance of both being odd   

 Nov 9, 2018
 #4
avatar+6252 
0

deleted

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 Nov 9, 2018
edited by Rom  Nov 9, 2018

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