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 Oct 1, 2018
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a) Yes, as long as a and b are allowed to be complex numbers.  Consider the simple parabola

 

y=x2+1with complex roots ±ithis can be written as (xi)(x+i)=x2+ixix+(i)(i)=x2+1

 

b) No.  Consider a general cubic polynomial

 

y=ax3+bx2+cx+d

 

as x,the x3 term dominates everything and yas x+, likewise the x3 term dominates and y+somewhere along the way it's got to cross the x axis and at that point y=0 at a real value of x

 Oct 1, 2018

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