Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
2
1
avatar+4 

Find the area of triangle ABC

 

[asy]
unitsize (2 cm);

pair A, B, C, D, E, F, H;

A = (0,2);
B = (-1,0);
C = (1,0);
D = (0,0);
E = (B + reflect(A,C)*(B))/2;
F = (C + reflect(A,B)*(C))/2;
H = extension(A,D,B,E);

draw(shift((-0.1,0))*(A--H), gray(0.7), Arrows(6));
draw(shift((-0.1,0))*(D--H), gray(0.7), Arrows(6));
draw(A--B--C--cycle);
draw(A--D);
draw(B--E);
draw(C--F);
draw(rightanglemark(A,D,C,3));
draw(rightanglemark(B,E,A,3));
draw(rightanglemark(C,F,B,3));
add(pathticks(B--D, n = 1, s = 4));
add(pathticks(C--D, n = 1, s = 4));

label("$A$", A, N);
label("$B$", B, SW);
label("$C$", C, SE);
label("$D$", D, S);
label("$E$", E, NE);
label("$F$", F, NW);
label("$H$", H, dir(0));
label("$5$", (A + H)/2 + (-0.1,0), W, red);
label("$3$", (H + D)/2 + (-0.1,0), W, red);
[/asy]

 
 Mar 30, 2025
 #1
avatar+40 
0

I solved this problem before.  The answer is 10*sqrt(5).  Hope this helps!

 Mar 30, 2025

1 Online Users