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Find all real numbers t such that $\frac{2}{3} t - 1 < t + 7 \le -2t + 15$ . Give your answer as an interval.

Guest Jul 17, 2019

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Find all real numbers t such that $\frac{2}{3} t - 1 < t + 7 \le -2t + 15$ . Give your answer as an interval.

Hello Guest!

$\frac{2}{3} t - 1 < t + 7 \le -2t + 15\\ -8 <\frac{1}{3}t\\ \color{blue}t<24$

$ $

$t+7\le-2t+15\\ -8\le -3t\\\color{blue}t\le24$

$t\in \{ \mathbb{R}|t<24\}$

!

asinus Jul 17, 2019

edited by asinus Jul 17, 2019
edited by asinus Jul 17, 2019

asinus · Answer 1 · 2019-07-17T09:53:56

Find all real numbers t such that $\frac{2}{3} t - 1 < t + 7 \le -2t + 15$ . Give your answer as an interval.

Hello Guest!

$\frac{2}{3} t - 1 < t + 7 \le -2t + 15\\ -8 <\frac{1}{3}t\\ \color{blue}t<24$

$ $

$t+7\le-2t+15\\ -8\le -3t\\\color{blue}t\le24$

$t\in \{ \mathbb{R}|t<24\}$

!

hectictar · Answer 2 · 2019-07-18T12:24:03

In order from oldest to newest:

Answers by CPhill and me:	https://web2.0calc.com/questions/help_49470
Second answer by CPhill:	https://web2.0calc.com/questions/help_85516
Answer by heureka:	https://web2.0calc.com/questions/help_71861
Second answer by me:	https://web2.0calc.com/questions/help_31003
Found from first page of search results here.