+59 All help is appreciated. If you only know one question please still submit it. I need all the help I can get. Thanks! 
1) In the multipication question below, find the product abcd:
7 a
x b 6
a a a
6 6 6
7 d c a
2) The function a*b is defined as a*b = a2b-a+b. Find the value of 2*(1*(2*(1*(2*1)))).
3) Find the sum of the proper divisors of the sum of the proper divisors of the number 432.
+33615 1) a = 4, b = 9, You should be able to work out c and d easily from this.
3) 722. I just used WolframAlpha to answer this. (Edited to correct answer - see asdf below).
+532 isnt 808 the sum of the proper divisors of 432?
i thought you had to do it twice.
so you would have 2^3*101
then using formulas, you get 15*102 or 1530
then take away 808 to get 722.
+532 ok so number two.
1. calculate the first 2*1
2*1 is 4-2+1 or 3.
2. now you have 2*(1*(2*(1*3))).
calculate 1*3.
1*3 is 3-1+3 or 5.
3. now you have 2*(1*(2*5)).
calculate 2*5.
2*5 is 20-2+5 or 23.
4. now you have 2*(1*23).
calculate 1*23.
1*23 is 23-1+23 or 45.
5. just calculate 2*45.
this is 180-2+45 or 225-2 or 223.
HOPE THIS HELPED!
