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${1 \over 2^3} \times {1 \over 2} \times {4 \choose 1} = {4 \over 16} = \color{brown}\boxed {1\over 4}$

Explanation:

There is a ${1 \over 2} \times {1 \over 2} \times {1 \over 2}$ chance of the successes ($3$ tails)

There is a $1 \over 2$ chance of failure ($1$ head)

There are $4 \choose 1$ ways to order the failure (the same as $4 \choose 3$, which counts the ways to order the successes.)