If m is a real number and 2x^2+mx+8 has two distinct real roots, then what are the possible values of m? Express your answer in interval notation. Thanks
2x^2 + mx + 8
If we have two distinct real roots, then this will be true
m^2 - 4 (2)(8) > 0
m^2 - 64 > 0
add 64 to both sides
m^2 > 64
So either
m > 8 or m < -8
So.....the solution is (-infinity, -8) U (8, infinity)
