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When the positive integer x is divided by each of 4, 5, 6, and 7, it has a remainder of 3. What is the sum of the three smallest possible values of x?

 Jul 9, 2021
 #1
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The sum of the three smallest possible values of x is 858.

 Jul 9, 2021
 #2
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When the positive integer x is divided by each of 4, 5, 6, and 7,

it has a remainder of 3.
What is the sum of the three smallest possible values of x?

 

x3(mod4)x3(mod5)x3(mod6)x3(mod7)

 

sum=(3+0×lcm(4, 5, 6, 7))+(3+1×lcm(4, 5, 6, 7))+(3+2×lcm(4, 5, 6, 7))sum=3+(3+420)+(3+2×420)sum=3+423+843sum=1269

 

laugh

 Jul 10, 2021
edited by heureka  Jul 10, 2021

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