A.) Geometric, sum of all terms is gotta be either -infinite, or all of that added up, I don't have the patience to work that out.
B.) No.
C.) 1+2+4+8+16+32+64+128+256=511, so n=9
D.) So uhh, I'm confused, but I think I get it. It's 4550, because 650+600+550+450...+150+100+50+0=4550
Someone smarter than me can do B.) because I'm lazy.
Yay!
A) geometric sequence, and the sum is just −512+256+128+⋯+2+1512=−1023512.
(notice that 1023 is one smaller than 1024, which is 2^10)
B) Idk if my solution is even close to optimal, but here it is:
Let the common difference be x. Then,
(35−6x)+(35−5x)+(35−4x)+(35−3x)+(35−2x)+(35−x)+(35)+(35+x)=2208(35)−20x=220−20x=−60x=3
The common difference is therefore equal to 3
The first term is just 35−6(3)=17
varvaax lmao I'm not that good :)