Help me plz.

y/3 + 1 = (y + 3)/y

==> (y + 3)/3 = (y + 3)/y

==> y = 3

The only solution is y = 3.

$\frac{y}{3}+1=\frac{y+3}{y}$

$y^2+3y=3\left(y+3\right)$                          (multiply both sides by 3y)

$y^2+3y=3y+9$                              (distribute right side)

$y^2=9$                                                 (subtract both sides by 3y)

$y=3,\:y=-3$                                  (final answer)