+1713 I am doing "Equations" in Algebra 2 in Khanacdemy and stumbled on this problem:
Find all the Intersecting points of a circle and a line:
Circle equation :(x−1)2+(y−1)2=1
Line equation :y=2x+1
And I tried the following but I am not sure if it is correct:
Since y=2x+1, we plug it into the circle equation.(line 1):(x−1)2+(y−1)2=1(line 2):(x−1)2+(2x+1−1)2=1(line 3):(x−1)2+(2x)2=1(line 4):x2−2x+1+4x2=1(line 5):5x2−2x+1=1(line 6):5x2−2x=0(line 7):x(5x−2)=0x=0x=2/5
From there, I do not know what to do...
It would be great if you could help me from there and tell me if I am on the right path.
-Tommarvoloriddle
EDITS:
Problem Link:
https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:eq/x2ec2f6f830c9fb89:quad-sys/e/quadratic-systems?modal=1
Videos with the problem link:
Circle and line:
https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:eq/x2ec2f6f830c9fb89:quad-sys/v/systems-of-nonlinear-equations-3?modal=1
Parabola and line:
https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:eq/x2ec2f6f830c9fb89:quad-sys/v/line-and-parabola-system?modal=1
No solution:
https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:eq/x2ec2f6f830c9fb89:quad-sys/v/non-linear-systems-of-equations-3?modal=1
+2864 I am not sure on this one but I would just plug back in the original equations.
