Help me please

In a triangle EFG, given e = 525, g = 421, E = 130 degrees and 50 minutes, what is the measure of angle G?

$\begin{array}{rcll} \frac{ \sin{(G)} } {g} &=& \frac{ \sin{(E)} } {e} \quad & | \quad :g \\ \sin{(G)} &=& \frac{g}{e} \cdot \sin{(E)} \\ \sin{(G)}&=& \frac{421}{525} \cdot \sin{( 130+\frac{50}{60} )} \\ \sin{(G)}&=& \frac{421}{525} \cdot \sin{( 130.833333333 )} \\ \sin{(G)}&=& \frac{421}{525} \cdot 0.75661478287 \\ \sin{(G)}&=& 0.80190476190 \cdot 0.75661478287 \\ \sin{(G)}&=& 0.60673299731 \quad & | \quad \arcsin{() }\\ G&=& \arcsin{(0.60673299731) } \\ G&=& 37.3536504319^{\circ} \\ \end{array}$