Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
+1
853
3
avatar+25 

1) Let  f(x)={3xif x<3,3xif x3. Find f(2)+f(3)+f(4). 

2) Let f(x)={2xif x<0,x2if x0. Find the range of f(x) in interval notation.

3) Find the area of the region that lies below the graph of y = 3 - |x - 1| but above the -axis.

 May 18, 2019
 #1
avatar+9488 
+2

1)

 

f(x)={3xif x<3,3xif x3.

 

 

Let's find  f(2)

 

2  <  3     so  we use   f(x)  =  3x

 

f(2)  =  3(2)

 

f(2)  =  6

 

Let's find  f(3)

 

3  ≥  3     so we use   f(x)  =  3x

 

f(3)  =  33

 

f(3)  =  27

 

Let's find  f(4)

 

4  ≥  3  so we use   f(x)  =  3x

 

f(4)  =  . . .?  Can you figure this one out?

 May 18, 2019
 #2
avatar+9488 
+3

2)
f(x)={2xif x<0,x2if x0.

 

Let  y  =  f(x)  so we can say that...

 

The range includes the smallest possible y value to the biggest possible y value.
 

A graph might help:

 

The smallest possible y value is  0

 

There isn't a biggest possible y value because we can always find a bigger one, so we say it's  ∞

 

So the range is  [0, ∞)

 May 18, 2019

2 Online Users