+116 a,b, and c are constants such that the quadratic ax^2 + bx + c can be expressed in the form 2(x - 4)^2 + 8. When the quadratic 3ax^2 + 3bx + 3c (for the same values of a, b, and c) is expressed in the form n(x - h)^2 + k, what is h?
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+6252 2(x−4)2+8=2(x2−8x+16)+8=2x2−16x+32+8=2x2−16x+40a=2, b=−16, c=403ax2+3bx+3c=6x2−48x+1206(x2−8x+20)=6((x−4)2+4)=6(x−4)2+24h=4Having gone through all that it's pretty clear to see that this should be so since multiplying all the constants by 3 just has the effect of scaling the parabolait's location remains unchanged. The x coordinate of the vertex of the original parabolawas 4, and thus we expect that the scaled parabola's vertex also has an x coordinate of 4
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