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In cyclic quadrilatera $PQRS,$

$\frac{\angle P}{2} = \frac{\angle Q}{3} = \frac{\angle R}{4}.$
Find the largest angle of quadrilateral PQRS, in degrees.

Guest Apr 9, 2020

tertre · Answer 1 · 2020-04-09T06:07:55

The sum of the opposite angles in a cyclic quadrilateral sum to 180 degrees.

Thus, p=2/3q, q=q, r=4/3q

2/3q+4/3q=180

6/3q=180

q=90

p=60

r=120

s=90

And, the largest angle is angle r, which measures 120 degrees.