Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
+1
1484
4
avatar+2499 

In the xy-plane, line L and K are parallel.Line Lpasses through the point (-1,-6) and the vertex of the parabola with the equation y=-2(x-1)^2+2 if the point (r,s) lies on the line K, which of the following is another point on line K

A) (r+1, s+4)

B) (r-1, s+4)

C) (r+1,s-4)

D) (r+4, s+t)

E) (r-4, s-4)

 Dec 17, 2015

Best Answer 

 #3
avatar+129898 
+15

Here's a graph that demonstrates Melody's answer.....

 

 

 

cool cool cool

 Dec 25, 2015
 #1
avatar+8581 
+5

I hate graph's too, My friend!

I wish I could help you. :(

 Dec 17, 2015
 #2
avatar+118680 
+15

Hi Solveit,

 

In the xy-plane, line L and K are parallel.Line Lpasses through the point (-1,-6) and the vertex of the parabola with the equation y=-2(x-1)^2+2 if the point (r,s) lies on the line K, which of the following is another point on line K

A) (r+1, s+4)

B) (r-1, s+4)

C) (r+1,s-4)

D) (r+4, s+t)

E) (r-4, s-4)

 

Do you still need and answer to this question - it is a bit old now.

I'll just give you an outline,

 

L passes thought (-1,-6)  and  (1,2)  so the gradient of L is     (2--6)/(1--1) = 8/2 = 4/1

K is a paralel line

one point on k is  (r,s)  so another point would be  (r+1,s+4)        [ run 1 ans rise 4]

 

So A is the answer.

If you need me to draw a pic or something, Let me know :)

 Dec 18, 2015
 #3
avatar+129898 
+15
Best Answer

Here's a graph that demonstrates Melody's answer.....

 

 

 

cool cool cool

CPhill Dec 25, 2015
 #4
avatar+2499 
0

thanks everybody ! and merry christmas ! :)

 Dec 25, 2015

2 Online Users

avatar