If a hash/password is 64 characters long and consists out of 36 possible characters (a-z, 0-9). How many combinations of the hash/password do I have if I exclude the possibility that I have more than 2 same characters every 3+ characters. Example: "aa22dd" is allowed "aaa22dd" is not allowed
+2499 i think:
the first two can be any number so there is 36 possibilities on the third you are not allowed to repeat so yo you have 35 posibilities on the fourth one you can put any character so you have 36 and so on:
(36-2)/2=17
36^2*35^17*36^17 = 65902860965567704608604298035681925529600000000000000000
i think i understood it wrong that is why i get a very big number :)
