How many real numbers are not in the domain of the function
\(f(x) = \frac{1}{x-64} + \frac{1}{x^2-64} + \frac{1}{x^3-64}~?\)
This means that either x-64, x^2-64, or x^3-64 is 0. so x can be 64, 8, -8, or 4 for a total of 4 solutions.
+273 
