+64 What is the value of $(a+b)\sqrt{cd}$ if $a = 2$ , $b = 4$, $c = 3$, and $d = 12$?
+1946 We have the equation (a+b)√cd
We have all the dimensions for us to solve the problem.
Plugging in all the numbers given, we get
(2+4)√3(12)=6√36=6(6)=36
So 36 is our final answer.
Thanks! :)
+972 a = 2 b = 4 c = 3 d = 12
(a+b)\sqrt{cd} = (6 + 6) \sqrt{24} = 24*sqrt(3)
+1946 We have the equation (a+b)√cd
We have all the dimensions for us to solve the problem.
Plugging in all the numbers given, we get
(2+4)√3(12)=6√36=6(6)=36
So 36 is our final answer.
Thanks! :)
