grtw

By "6 eyes", you mean 12?

If so the probabilty is =125/1,296 =~9.65%

Andre throws 4 dices. How many possibilities are there to throw a total of 6 eyes?

$\begin{array}{|r|r|} \hline \text{eyes} & \text{possibilities} \\ \hline 1 & 0 \\ 2 & 0 \\ 3 & 0 \\ 4 & 1 \\ 5 & 4 \\ \color{red}6 & \color{red}10 \\ 7 & 20 \\ 8 & 35 \\ 9 & 56 \\ 10 & 80 \\ 11 & 104 \\ 12 & 125 \\ 13 & 140 \\ 14 & 146 \\ 15 & 140 \\ 16 & 125 \\ 17 & 104 \\ 18 & 80 \\ 19 & 56 \\ 20 & 35 \\ 21 & 20 \\ 22 & 10 \\ 23 & 4 \\ 24 & 1 \\ \hline & \text{sum } = 1296\\ \hline \end{array}$