Assume that $f(3) = 4$. Name a point that must be on the graph of $y= 1/5*f(5x + 5) - 5$.
\(y= 1/5\cdot f(5x + 5) - 5\)
\(y= 1/5\cdot f(5x + 5) - 5, x = -2/5\)
\(y= 1/5\cdot 4- 5\)
\(y = 6-5\)
\(y = 1\)
The point will be \((-2/5,1)\)
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