Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1
First, let's note something really important for the problem.
We have P1P2P3⋯P10, which actually just forms a regular decagon!
P1P2+P2P3+P3P4+⋯+P9P10+P10P1is just the perimeter of that decagon.
The length of a decagon can be found with formula radius2(−1+√5)
Thus, the perimeter is 10(1/2)(−1+√5)=5(−1+√5)≈6.18
So our answer is approximately 6.18
Thanks! :)