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Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1

 Jun 13, 2024
 #1
avatar+1952 
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First, let's note something really important for the problem. 

We have P1P2P3P10, which actually just forms a regular decagon!

P1P2+P2P3+P3P4++P9P10+P10P1is just the perimeter of that decagon. 

 

The length of a decagon can be found with formula radius2(1+5)

 

Thus, the perimeter is 10(1/2)(1+5)=5(1+5)6.18

 

So our answer is approximately 6.18

 

Thanks! :)

 Jun 13, 2024

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