+1786 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1950 Let's note that If AD = AB then ∠ABD=∠ADB
This means that ∠ABD=(180−17)/2=81.5°
So 81.5 is the answer.
Thanks! :)
