+216 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1952 First, let's note that if AD = AB, then ∠ADB=∠ABD
So, this means we have ABD=(180−17)/2=81.5°
Our final answer is thus 81.5
Thanks! :)
