+1800 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1953 To solve this problem, let's note something really important first.
Since in the problem, we have AD=AB, then we can conclude that ∠ABD=∠ADB
Thus, we can easily solve the problem from here. We can write the equation
ABD=(180−17)/2=81.5°
Thus, our answer is 81.5
Thanks! :)
