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In triangle ABC, AC=BC and ACB=90. Points P and Q are on ¯AB such that P is between A and Q and QCP=45. If cos ACP = 2/3, then find cos BCQ.

 Mar 2, 2024
 #1
avatar+130479 
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Impossible

To see why

 

 

ACB  = 90°

 

QCP  = 45°

 

If the cos ACP  = 2/3....then arcos  (2/3)  ≈ 48.2°

 

But this means that   QCP + ACP  =  45 + 48.2  =  93.2°   which would be >  ACB

 

cool cool cool

 Mar 3, 2024

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