In triangle ABC, the angle bisector of ∠BAC meets ¯BC at D. If ∠BAC=60∘, ∠CAD=45∘, and AD=24, then find the area of triangle ABC.
let me elaborate on what BRAINBOLT said.
See, if D lies on the angle bisector of BAC, and angle BAC is 60 degrees, then angle CAD cannot be 45.
This is because since D lies on the bisector, CAD would therefore be half of BAC, which is 30.
So, this problem is invalid,
Thanks! :)