Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 90^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle XZW$, in degrees.
First, let's note that XZW will form a triangle
From the problem, we have that
∠ZXW=90∘∠XWZ=60∘
Thus, we can easily find XZW since it's the last angle in the triangle.
So ∠XZW=180−90−60=30∘
Thanks! :)