+92 AB and CD meet at point E. m∠AEC = 18 + 5x. Find m∠BEC, m∠BED, and ∠AED in terms of x.
+36915 AEC and BED are equal (opposite angles) BED = 18 + 5x
Angles AED and BEC are also equal opposite angles and added to the angle next to them (18+5x) equal 180
So AED = BEC AED +18+5x=180 AED = 162-5x = BEC
+382 Angle BED is 18+5x
Angle DEA is 162-5x
Angle CEB is 162-5x
Angle CEB = Angle DEA
Angle BED = Angle CEA
