Geometry Question. I would appreciate the help please.

ok, lets say the length and width of the photo is l and w.

then, $2\left(l+w\right)=23$

and if the frame is 1 inch, $\left(l+1+1\right)\left(w+1+1\right)=58.5$

then we just solve the system of equations and get l = 7 and w = 4.5 so the area is 31.5

Do you understand what mworkhard has presented so far?  I will assume so ....

2(L+W) = 23 (1)

(L+2)(W+2)=58.5  (2)

LW+2(W+L)+4=58.5

sub in (1)

LW+23+4=58.5

LW+27=58.5

LW=31.5

L=31.5/W

sub into (1) to find W

2(L+W) = 23 (1)

$2(\frac{31.5}{W}+W) = 23 \\ \text{mult both sides by W}\\ 2W(\frac{31.5}{W}+W) = 23W \\ 63+2W^2=23W\\ 2w^2-23w+63=0\\ w=\frac{23\pm\sqrt{529-504}}{4}\\ w=\frac{23\pm\sqrt{25}}{4}\\ w=\frac{23\pm5}{4}\\ w=4.5\;or\; 7$

Length = 7  width =4.5 inches

omg how did i not see this! Here is how u can solve the system:

1. Isolate $l$ in $2(l+w)=23$ and get $l=\frac{23}{2}-w$
2. Plug the solutions $l=\frac{23}{2}-w$ into $\left(l+1+1\right)\left(w+1+1\right)=58.5$
3. For $\left(l+1+1\right)\left(w+1+1\right)=58.5$ subsitute $l$ with $\frac{23}{2}-w: \:\:w=\frac{9}{2},l=7$

Where I got my steps: https://www.symbolab.com/solver/step-bystep/2%5Cleft(l%2Bw%5Cright)%3D23%2C%20%5Cleft(l%2B1%2B1%5Cright)%5Cleft(w%2B1%2B1%5Cright)%3D58.5