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Triangle ABC has a right angle at angle B. Legs AB and CB are extended past point B to points D and E, respectively, such that angle EAC = angle ACD = 90 degrees. Prove that EB * BD = AB * BC.

 

Below is the diagram representing the described triangle.

 

Can you please provide a step-by-step solution?

 

Also, it would be helpful if you could solve this without trignometry, because that is too complex for someone with my understanding of geometry. I think that you prove similarity by SSS, SAS, or AA, but I am not sure. 

 

Thank you for your help!

 Mar 10, 2017

Best Answer 

 #1
avatar+26397 
+5

Triangle ABC has a right angle at angle B. Legs AB and CB are extended past point B to points D and E, respectively, such that angle EAC = angle ACD = 90 degrees. Prove that EB * BD = AB * BC.

 

Below is the diagram representing the described triangle.

 

Geometric mean theorem:

(1)AB2=EBBC(2)BC2=ABBD(1)(2):AB2BC2=EBBCABBD|:(ABBC)ABBC=EBBD

 

 

laugh

 Mar 10, 2017
 #1
avatar+26397 
+5
Best Answer

Triangle ABC has a right angle at angle B. Legs AB and CB are extended past point B to points D and E, respectively, such that angle EAC = angle ACD = 90 degrees. Prove that EB * BD = AB * BC.

 

Below is the diagram representing the described triangle.

 

Geometric mean theorem:

(1)AB2=EBBC(2)BC2=ABBD(1)(2):AB2BC2=EBBCABBD|:(ABBC)ABBC=EBBD

 

 

laugh

heureka Mar 10, 2017

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