+185 Suppose that a, b, and c are real numbers for which
\(\begin{align*} a^2b^2 &= 28, \\ b^2c^2 &= 21, \text{ and}\\ a^2c^2 &= 27, \end{align*}\). If a < b < c, find 3b. Don't know where to start. Any help or hints will be appreciated.
+185 Okay, for a second I forgot that negative numbers could be squared to get a positive number. This thread is useless now, sorry for making it...
