find the positive constant c that makes 4z^2+cz+0 the square of a binomial.
4z^2 + cz + 0 ???
We can't get a squared binomial out of this Blizzardshine....you sure you wrote it correcty ??
Oh, whoops! It's supposed to be 9.
OK.....that's WAY better....LOL!!!
4z^2 + cz + 9
We want to write ( az + b)^2
Easy....
Take the square root = 4 = 2 = a
Take the square root of 9 = 3 = b
So
(2z + 3)^2 =
(2z + 3) (2z + 3) =
4z^2 + 3*2z + 3*2z + 9 =
4z^2 + 12z + 9
c =12
+248 
