find the area of the triangle having the indicated sides and angle. C=84.5°, a=32, b=40

find the area of the triangle having the indicated sides and angle:

C=84.5°, a=32, b=40

$$\boxed{ 2\cdot A = a\cdot b \cdot \sin{( C ) } }\\\\ \small{\text{$2\cdot A = 32 \cdot 40 \cdot \sin{(84.5\ensurement{^{\circ}}}) $}} \\ \small{\text{$ 2\cdot A = 1280 \cdot 0.99539619837 $}}\\ \small{\text{$ 2\cdot A = 1274.10713391 $}}\\ \small{\text{$ A = 637.053566955 $}}$$