Find all values of t such that 6^(3t - 1) = 36^t.
\(6^{3t - 1} = 36^t\)
\(6^{3t-1} = {6^2}^t\)
\(6^{3t-1} = 6^{2t}\)
\(3t - 1 = 2t\)
Can you take it from here?
+2666 
