exponent and log

0.0256 = e^(.46t) how to solve this equation ?? steps please

$\begin{array}{|rcll|} \hline 0.0256 &=& e^{(0.46\cdot t)} \qquad & | \qquad ln() \\ \ln(0.0256) &=& 0.46\cdot t \qquad & | \qquad : 0.46 \\ \frac{ln(0.0256)}{0.46 } &=& t \\ t &=& \frac{ln(0.0256)}{0.46 } \\ t &=& \frac{-3.66516292750}{0.46 } \\ t &=& -7.96774549456 \\ \hline \end{array}$

     0.0256 = e^(.46t)

   e^(0.46)t=0.0256

lne^(0.46)t=ln0.0256

   0.46t*lne=ln0.0256         lne=1

         0.46t=ln0.0256          |:0.46

                t=ln0.0256/0.46

                t=-7,967745495...