Enter all solutions to \({(x-2)}^{25-x^2} = 1\)
If I am only dealing with real numbers then
x-2=1
x=3
or
x-2 could be -1 if 25-x^2 is even
if x=1 25-x^2 = 24 and that is even
so
x=1 or x=3
How about when the exponent is equal to zero (when x is equal to \(\pm 5\))?
your right!!! the answer is 1,3,5,-5
Yes, good spotting. :)
