How many values of \(x\) with \(0^\circ\le x < 990^\circ\) satisfy \(\sin x = -0.31\)?
Thanks for any help given!
Hello proyaop!
\(\frac{900^o}{360^o}=2.5\ \to 2\cdot 2=\color{blue}4\)
proyaop, the negative sine values are in the third and fourth quadrants!
4 values satisfy sin x = -0.31.
!
It was 5 :(
thanks asinus and thx for the reminder melody :D
Don't be rude Proyaop, it gets you nowhere.
Besides I think you are better than that.
When someone tries to help you, you say thank you! (And you do not take points off them!)
Do you still want help? You didn't state, one way or the other.
+1622 
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