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e^i*1.5708

 Mar 17, 2015

Best Answer 

 #1
avatar+26396 
+10

e^i*1.5708 ?

eiφ=cos(φ)+isin(φ)

φ=π2=1.57079632679

ei1.57079632679=eiπ2=cos(π2)+isin(π2)=0+i1=i

e^i*1.5708  = i

 Mar 18, 2015
 #1
avatar+26396 
+10
Best Answer

e^i*1.5708 ?

eiφ=cos(φ)+isin(φ)

φ=π2=1.57079632679

ei1.57079632679=eiπ2=cos(π2)+isin(π2)=0+i1=i

e^i*1.5708  = i

heureka Mar 18, 2015
 #2
avatar+118703 
+3

Thanks Heureka,

 Mar 18, 2015

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