How do i get 0 if my question looks like this? x/2+(3*2)+sqr(16)
If x=-20.
PROOF
x2+(3∗2)+√16=0
x2+6+4=0
x2+10=0
x2=−10
x=−20
CHECK
−202+6+4=0
−10+10=0
0=0
Thx m(sqr(64))