Does 1/2x + 4y = 0 represent a direct variation ?
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Manipulating this a bit, we have
y = -(1/8)x
Notice that this is just a line with a negative slope that passes through the origin.....as x increases, y decreases
Thus we have an inverse variation.
Does 1/2x + 4y = 0 represent a direct variation ?
---------------------------------------------------------------------------------------------------------------------------
Manipulating this a bit, we have
y = -(1/8)x
Notice that this is just a line with a negative slope that passes through the origin.....as x increases, y decreases
Thus we have an inverse variation.