Processing math: 100%
 
+0  
 
0
39
1
avatar+216 

Points $A,$ $B,$ and $C$ are given in the coordinate plane. There exists a point $Q$ and a constant $k$ such that for any point $P$,
PA^2 + PB^2 + PC^2 = 3PQ^2 + k.
If $A = (7,-11),$ $B = (10,13),$ and $C = (18,-22)$, then find the constant k.

 Jul 1, 2024

Best Answer 

 #1
avatar+1953 
+1

Let's set up some variables to solve this problem. 

Let's first set that P=(x,y)

 

Now, from the problem, we can write the complicated equation of

PA2+PB2+PC2=(x7)2+(y+11)2+(x10)2+(y13)2+(x18)2+(y+22)2

 

Now, we have to simplify this gigantic equation. By expanding and combining lots of like terms, we get that

3x270x+3y2+40y+12473[x270/3x+y2+40/3y]+1247

 

Now, we simplfy complete the square for x and y to achieve our x and y values for point Q, which will be crucial. 

Completing the square, we have

3[x270/3x+4900/36+y2+40/3y+1600/36]+12474900/121600/123[(x70/6]2+(y+40/6)2]+2116/3

 

Now, from this, we can tell what Q has for their x and y value. 

We have that Q = (70/6, -20/3)

 

Thus, we know that

k=2116/3

 

So 2116/3 is our final answer. 

 

Thanks! :)

 Jul 1, 2024
 #1
avatar+1953 
+1
Best Answer

Let's set up some variables to solve this problem. 

Let's first set that P=(x,y)

 

Now, from the problem, we can write the complicated equation of

PA2+PB2+PC2=(x7)2+(y+11)2+(x10)2+(y13)2+(x18)2+(y+22)2

 

Now, we have to simplify this gigantic equation. By expanding and combining lots of like terms, we get that

3x270x+3y2+40y+12473[x270/3x+y2+40/3y]+1247

 

Now, we simplfy complete the square for x and y to achieve our x and y values for point Q, which will be crucial. 

Completing the square, we have

3[x270/3x+4900/36+y2+40/3y+1600/36]+12474900/121600/123[(x70/6]2+(y+40/6)2]+2116/3

 

Now, from this, we can tell what Q has for their x and y value. 

We have that Q = (70/6, -20/3)

 

Thus, we know that

k=2116/3

 

So 2116/3 is our final answer. 

 

Thanks! :)

NotThatSmart Jul 1, 2024

1 Online Users

avatar