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if z is a complex number such that z+1/z=3

 

what is the value of z2010+1/z2010?

 

Thanks for any hints, help, or answers!

 May 31, 2021
 #1
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By Demoivre's Theorem, z^2010 + 1/z^2010 = 1.

 May 31, 2021
 #2
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After answering 1, it said it was incorrect and that the actual answer is -2.  Thanks for answering though!

Guest May 31, 2021
 #3
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+2

if z is a complex number such that z+1z=3
what is the value of z2010+1z2010?

 

1. |z|= ?

z+1z=3|Let z=a+bia+bi+1a+bi=3a+bi+1(a+bi)(abi)(abi)=3|(a+bi)(abi)=|z|2a+bi+abi|z|2=3a+a|z|2=3+bibi|z|2=0=3bibi|z|2=0bi=bi|z|2|z|2=bibi|z|2=1or|z|=1

 

2. φ= ?

z=|z|eiφ||z|=1z=eiφz=cos(φ)+isin(φ)1z=z1=(|z|eiφ)1=|z|1(eiφ)1=1|z|eiφ(1)=1|z|ei(φ||z|=1=ei(φ=cos(φ)+isin(φ)1z=cos(φ)isin(φ)z+1z=cos(φ)+isin(φ)+cos(φ)isin(φ)z+1z=2cos(φ)|z+1z=33=2cos(φ)cos(φ)=32φ=30

 

3. z2010= ?

z2010=(|z|eiφ)2010=|z|2010(eiφ)2010=12010ei2010φ=ei2010φ=cos(2010φ)+isin(2010φ)|φ=30=cos(201030)+isin(201030)=cos(180)+isin(180)z2010=1

 

4. 1z2010= ?

1z2010=(|z|eiφ)2010=|z|2010(eiφ)2010=12010ei(2010φ)=ei(2010φ)=cos(2010φ)+isin(2010φ)=cos(2010φ)isin(2010φ)|φ=30=cos(201030)isin(201030)=cos(180)isin(180)1z2010=1

 

z2010+1z2010=1+(1)z2010+1z2010=2

 

laugh

 Jun 1, 2021

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