In how many ways can 6 chocolates be distributed among 3 children? A child may get any number of chocolates from 0 to 6 and all the chocolates are identical.
This is similar to distributing k identical balls into n distinct boxes......where we have no restrictions [ any box can be empty ]
This is given by
C ( n + k -1 , n -1) = C ( 3 + 6 - 1 , 3 - 1) = C ( 8, 2) = 28 ways
If each child can have 1 or more chocolates, then you have:
[6 - 1] C [3 - 1] =5C2 =10 ways.
+1347 
